Question
In a circle, two chords AB & CD are produced at P which
is outside the circle . If PA= 18 cm, AB= 12 cm , PC = 6 cm then find CD.Solution
We know that when AB & CD two chords intersect at point P, PA `xx` PB = PC `xx` PD So 18 `xx` (18 + 12) = 6 `xx` (6 + CD) 540 = 6 `xx` (6 + CD) 90 = 6 + CD CD = 84 cm
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