Divide Rs. 2,440 into two parts such that the first part after 10 years is equal to the second part after 8 years, compound interest being 20% per annum compounded yearly.
Let the first part be x and the second part be y. The first part after 12 years, = x (1+(20/100))10 The second part after 8 years, = y (1+(20/100))8 As given in the problem these two amounts are equal. So, y (1+(20/100))8= x (1+(20/100))10 Or y/x = (1+(20/100))2 Or y/x = 36/25 We have the x + y = Rs. 2,440 Using the ratio formula, y = 36/(36+25) × 2,440 = Rs. 1,440 x = 25/(36+25) × 2,440 = Rs. 1,000 Alternate method: y/x = (1+20/100)(difference between time) Or y/x = (1+20/100)(10-8) Or y/x = (1+20/100)2 Or y/x = (6/5)2 Or y/x = 36/25 We have the x + y = Rs. 2,440 Using the ratio formula, y = 36/(36+25) × 2,440 = Rs. 1,440 x = 25/(36+25) × 2,440 = Rs. 1,000
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * VÂ Â Â Â Â Â Â II. R * VÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â...
Statement: L = C; E ≥ M ≥ U ≥ C
Conclusion:
I. E > L
II. E = L
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
Statements: Â A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements: A > C ≥ B = D; E < F = G < H = I ≤ D
Conclusions:
I. B > E
II. D < E
III. E ≥ B
Statements: J $ K, K * T, T @ N, N © R
Conclusions:
 I. J $ T                  II.R * T               Â...
Statements: O< V ≤ N = P < S, R = Z ≥ Y = X > O
Conclusions:
I. R > N
II. X > P
III. R > O
Statement:X=Y ≥ Z > Q; Y < V ; W < Q
Conclusions:
I. V > W
II. Q > V
Statements: A & D, D # P, P @ Q, Q % R
Conclusions: I. D & R                    II. Q # A
...