Question
A certain sum invested in compound interest (compounded
annually) grows to 5040 in three years. If the rate of interest is 25% for the first year, 40% for the second year, and 50% for the third year, then what is the sum?Solution
Given - A= 5040, r₁=25%, r₂=40%, r₃=50% P=? So now - A=P[1+r₁/100] [1+r₂/100] [1+r₃/100] 5040=P [1+25/100] [1+40/100] [1+50/100] 5040=P [125/100] [140/100]]150/100] P = [5040×1000000]/125×140×150 =5040×80/14×15 =403200/210=40320/21 P=1920
More Compound Interest Questions
182 + 10 × 12 - ? = 312
53 – 8 = ? + 126
2850 ÷ 2.5 - ? × 42 = 300
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
Evaluate
32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 + 5)] + (6 ÷ 2 + 1)
What will come in place of (?) in the given expression.
[(24 ÷ 3) + (18 × 2)] - 5 = ?666(2/3)% of 30 - 116(2/3)% of 90 =?
√ [? x 11 + (√ 1296)] = 16
What will come in the place of question mark (?) in the given expression?
{122 + (66/4) + (252/8)} ÷ 8 = (?)1/2
(62 + 82 ) X ? = 80% of 500 - 25 X 4
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