A certain sum invested at compound interest of 10% p. a compounded annually, returns Rs. 6292 after 2 years. If a 20% greater sum is invested at a simple interest of 9% p. for ‘n’ years, then the interest received would be Rs. 2700. Find the value of 'n'.
Let the sum invested = Rs. P Then, total amount returned = Y × {1 +(10/100)}2 = 6292 Or Y × 1.21 = 5808 So, Y = 6292 ÷ 1.21 = 5200 The sum invested at simple interest = 52500 × 1.20= Rs. 6240 Simple interest received = 6240 × 9 × n ÷ 100=2700 56160n=270000 n=270000/56160 =4.8%
34 × 5 × 2 ÷ 6 + 7 × 5 + 13 = (?)× 6 – 754
15848 ÷ 4 – 793 × 6 + 3628 = 3 × ?
(7 ÷ 0.125) x (10 ÷ 10/3 ) = ?
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
120% of 25 + 80 X 2 = ?2 - 6
116 x (2/3)% of 420 + 666 x (2/3)% of 186 = 457 x (1/7)% of 126 + 555 x (5/9)% of 198 + ?
2/5 of 3/4 of 7/9 of 7200 = ?
4567.89 - 567.89 - 678.89 = ?
(72× 52+ 1555 )/(79+60) = 2000 ÷ ?
25% of 60 × 15% of 120 = 30% of (?)
