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First, calculate the amount after 3 years at 8% compound interest. Formula: A = P * (1 + r/100)^n A = 15000 * (1 + 8/100)^3 = 15000 * (1.08)^3 = 15000 * 1.256 = ₹18840 Now, reinvest ₹18840 at 5% compound interest for 2 years. A = 18840 * (1 + 5/100)^2 = 18895.50 * (1.05)^2 = 18840 * 1.1025 = ₹20771.1 Therefore, the total amount after 5 years is ₹20771 Answer: c) ₹20771
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
1540 ÷ 7 - 184 ÷ 8 = ?
12.232 + 29.98% of 539.99 = ? × 5.99
√256 * 3 – 15% of 300 + ? = 150% of 160
18 × 15 + 86 – 58 =? + 38
[5 X {(52 X 5) - 10} + 50 of 20] = ?
4(1/3) × 2(11/14) = 50% of ? + 86/11
(15 x 6 + 60% of 500 - 16 x 7) = ?
25% of 140 + 2 × 8 = ? + 9 × 5
If a nine-digit number 389x6378y is divisible by 72, then the value of √(6x + 7y) will be∶