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Let the center of the circle be (h, k), and the equation of the circle be (x - h)^2 + (y - k)^2 = r^2. Since the circle passes through (1, 2) and (2, -1): (1 - h)^2 + (2 - k)^2 = r^2 and (2 - h)^2 + (-1 - k)^2 = r^2. Also, the center lies on the line x - 2y + 3 = 0, so h - 2k + 3 = 0. Solve this system of three equations to find h, k, and r. After solving: h = 1, k = -2, and r^2 = 8. The equation of the circle is (x - 1)^2 + (y + 2)^2 = 8.
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