Find the Perpendicular distance between two lines
6x + 8y = 18, 12x + 16y =20
For finding the perpendicular distance between two lines ax + by = C1, ax + by = C2 Coefficients must be equal then Perpendicular Distance = |C1-C2|/√(a2+ b2) 6x + 8y = 18 …………(i) 12x + 16y =20…………..(ii) Multiplying equation (i) with 2 12x + 16y =36 Now the Perpendicular Distance = |36-20|/√(12² + 16²) = 16/20 = 0.8
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