Find the area of a rhombus.
A. Sum of the squares of the diagonals is 256 m².
B. Perimeter of the rhombus is 32 m.
C. Ratio of one diagonal and the side is 3:8
If d₁ and d₂ be the diagonals and a the length of the side of the rhombus then A. d₁²and d₂² = 4a² = 256 a² = 64 a = 8 P = 4a 32 = 4a 4 = a C. d₁ : a = 3 : 8 Therefore, by combining C and either A or B, the answer can be found.
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