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Let speed of boat = u, and stream = v From I: u + v= 16/2 = 8 km/hr From II: v = 2u/5 From III: u – v = 24/6 = 4 So solving I and II ‘u’ can be found. Similarly by solving II and III and by solving I and III
(74.93% of 640.11 + 3/4 of 359.79)² - (1/3 of 80.87 × 2)² = ?
Find the approximate value of Question mark(?). No need to find the exact value.
(639.78 ÷ 15.96) × 5 + 30.14% of 349.88 – √(224.95) ÷ 5...
? + 163.99 – 103.01 = 24.01 × 6.98
194.95 + 3.98 × 64.99 - ? = (10.99 + 9.02)2
(284.85 ÷ 15.09) x 2.22 + 51.17 = 157.69 - ?
?% of (140.31 ÷ 19.97 × 80.011) = 139.98
(168.24 ÷ 23.98) x 19.81 + ? = 176.33
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65
811.85 ÷ 28.05 + 462.16 – 23.06 × 17.95 = ?