Question
What was the per cent profit/loss made/incurred by
selling an article for Rs. 24000? Statement I. The ratio between the selling price and the cost price of the articles is 5 : 3 respectively. Statement II. The difference between the cost price and the selling price is Rs. 9600. In each of the following questions, a question followed by two statements numbered I and II are given. You have to read both the statements and then Give answerSolution
Selling Price = 36,000 From statement I Selling Price/Cost Price =5/4 Cost Price = 28,800 ∴ Profit % = (36,000 – 28,800)/28,800 × 100 = 25% From statement II It is not clear that Cost Price is greater than or less than Selling Price. Hence, the data in statement I is sufficient.
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0