What was the total compound interest on a sum after three years?
Statement I - The interest after one year was Rs. 200 and the sum was Rs. 1000.
Statement II - The difference between simple interest and compound interest on a sum of Rs. 2000 at the end of two years was Rs. 20
From statement I: r = (200 × 100)/1000 = 20% P = Rs. 1000 , r = 20%, t = 3 years Hence, from statement I we can find CI. From statement II: SI = (2000 × r × 2)/100 = 40r CI = 2000 [(1+(r/100)2) – 1] Therefore, CI – SI = 2000 [(1+(r/100)2) – 1] – 40r We can find the value of r from the above equation. Hence , CI can be determined.
345 = √2704 ÷ (?% of 104) + 7 3
Simplify the following expression
4567.89 - 567.89 - 678.89 = ?
756 + 432 – 361 + ? = 990
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
84% of 8400 + 42% of 6120 =?
(72 × 10 ÷ 20) × 10 = ?
(5/8) × 480 + (3/9) × 450 = (5/2) × ?
(13)2 - 3127 ÷ 59 = ? x 4
5490 ÷ 15 × 18 + 450 = ?