Find the ratio of average of selling price of each unit of articles 'B' and 'C' together to cost price of each unit of article 'A'
Given, 2x – y/2 = 90 Or, 4x - y = 180 ....... (I) And, 3y – x/2 = 35 Or, (6y - x) = 70 ........ (II) On adding equation (I) with 4 × equation (II), we have; 4x + (-4x) - y + (24y) = 180 + 70 X 4 Or, 23y = 460 So, y = 20 So, 4x = 180 + 20 ..... (From equation I) Or, x = 200 ÷ 4 = 50 So, marked price of article 'A' = 4 × 50 = Rs. 200 And, percentage discount offered on article 'A' = 1.25y% = 1.25 × 20% = 25% So, discount offered = 200 × 0.25 = Rs. 50 So, profit earned on article 'A' = 50 × 1.4 = Rs. 70 So, profit earned on article 'D' = 70 + 50 = Rs. 120 Marked price of article 'D' = Rs. 400 Percentage discount offered = 2y% = 2 × 20 = 40% So, discount offered = 400 × 0.4 = Rs. 160 ATQ; (120/160) × 100 = {z - (x/2)} Or, 75 = z - 25 So, z = 100 For article 'A': Marked price of the article = Rs. 200 Discount offered = Rs. 50 Selling price = 200 - 50 = Rs. 150 Profit earned = Rs. 70 So, cost price = 150 - 70 = Rs. 80 Average selling price of articles 'B' and 'C' together = (240 + 360) ÷ 2 = Rs. 300 Cost price of article 'A' = Rs. 80 So, required ratio = 300:80 = 15:4
2280.03 ÷ 59.98 x 59.9 = ? + 30.32
215.003X4.021 + 11.05 + 71.02 =?
5275 of 105% + 99.07 × 17.889 =?
...59.98% of 3200 + 50.28% of 2800 = 89.99% of 2800 + ?
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99
(84.92 + 235.17) ÷ (15.93 × 3.89) = ? ÷ 21.02
17.06 2 + √36.08 – (4.04/2.99) × 3.02 × 4.92 = ? × 4.99
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...