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Given, 2x – y/2 = 90 Or, 4x - y = 180 ....... (I) And, 3y – x/2 = 35 Or, (6y - x) = 70 ........ (II) On adding equation (I) with 4 × equation (II), we have; 4x + (-4x) - y + (24y) = 180 + 70 X 4 Or, 23y = 460 So, y = 20 So, 4x = 180 + 20 ..... (From equation I) Or, x = 200 ÷ 4 = 50 So, marked price of article 'A' = 4 × 50 = Rs. 200 And, percentage discount offered on article 'A' = 1.25y% = 1.25 × 20% = 25% So, discount offered = 200 × 0.25 = Rs. 50 So, profit earned on article 'A' = 50 × 1.4 = Rs. 70 So, profit earned on article 'D' = 70 + 50 = Rs. 120 Marked price of article 'D' = Rs. 400 Percentage discount offered = 2y% = 2 × 20 = 40% So, discount offered = 400 × 0.4 = Rs. 160 ATQ; (120/160) × 100 = {z - (x/2)} Or, 75 = z - 25 So, z = 100 For article 'A': Marked price of the article = Rs. 200 Discount offered = Rs. 50 Selling price = 200 - 50 = Rs. 150 Profit earned = Rs. 70 So, cost price = 150 - 70 = Rs. 80 Average selling price of articles 'B' and 'C' together = (240 + 360) ÷ 2 = Rs. 300 Cost price of article 'A' = Rs. 80 So, required ratio = 300:80 = 15:4
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PLATINUM
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EXAMINATION
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