Question
Two contractors, X and Y, are assigned to finish a
construction project that consists of three phases. Each contractor works at a constant rate for each phase. What is the total number of hours taken by Contractor X to complete all three phases? Statements: 1. The total hours worked by Contractor Y on all three phases is 80% of the total hours worked by Contractor X. Contractor Y worked for 200 hours in the first phase, 300 hours in the second phase, and 250 hours in the third phase. 2. Contractor X spent twice as much time on the first phase as Contractor Y. Contractor X's time spent on the second phase is 150% of the time spent on the first phase.Solution
From Statement 1: Contractor Y’s total time is 200 + 300 + 250 = 750 hours. This is 80% of the time taken by Contractor X, so Contractor X’s total time is 750 / 0.8 = 937.5 hours. this alone is sufficient. From Statement 2: Contractor X’s time in the first phase is twice Contractor Y’s, So without help of statement 1 answer can’t be calculated. Statement 2 alone is not sufficient. Correct Answer: (a) Statement 1 alone is sufficient, but statement 2 alone is not sufficient.
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