ATQ, Let the speed of trains ‘P’ and ‘Q’ be 4x km/hr and 5x km/hr, respectively Statement I: According to the question, Let the length of train ‘Q’ be ‘l’ metres (4x + 5x) × (5/18) = (300 + l)/20 Or, 100x = 600 + 2l So, data in statement I alone is not sufficient to answer the question. Statement II: (4x + 10) × (5/18) = 300/20 Or, 20x + 50 = 18 × 15 = 270 Or, 20x = 220 Or, x = 11 Therefore, speed of train ‘Q’ = 5x = 55 km/hr So, data in statement II alone is sufficient to answer the question. So, data in statement II alone are sufficient to answer the question, while the data in statement I alone are not sufficient to answer the question
180 ÷ 3 of 2 = 102 – ?
654.056 + 28.9015 × 44.851 – 43.129 = ?
√ (573 – 819 + 775) = ? ÷ 3
[1.45 X 1.45 X 1.45 + 0.55 X 0.55 X 0.55 + 4.785] = ?
(286 ÷ 11 + 14) × 5 = 40 + 25% of ?
14 × 11 + 25 – ? = 21% of 300
(3984 ÷ 24) x (5862 ÷ 40) = ?
20% of 10% of 900 + 84/12 = ?2
30, 39, 66, ? , 174, 255