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ATQ, Statement I: Let, time taken by 'C' to do the work with 100% efficiency = y days So, time taken by 'C' to do the work with 125% efficiency = 4y/5 days Therefore, time taken by 'A' to do the work = 4y/5 days Work done by 'A' and 'B' in one day = 5/4y + 1/12 = (15 + y)/12y So, (15 + y)/12y = 7/48 60 + 4y = 7y 3y = 60, y = 20 Therefore, 'C' will take 20 days to do the work with 100% efficiency. Work done by all three in one day = 1/20 + 7/48 = (12 + 35)/240 = 47/240 Required number of days = 240/47 days Statement I alone is sufficient to answer the question Statement II: Number of days taken by 'A' to do the work with 100% efficiency = 20 × 4/5= 16 days Let, time taken by 'B' to do the work = x days Then, time taken by 'C' to do the work = (x + 8) days Statement II alone is not sufficient to answer the question.
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