Start learning 50% faster. Sign in now
ATQ, Statement I: Let, time taken by 'C' to do the work with 100% efficiency = y days So, time taken by 'C' to do the work with 125% efficiency = 4y/5 days Therefore, time taken by 'A' to do the work = 4y/5 days Work done by 'A' and 'B' in one day = 5/4y + 1/12 = (15 + y)/12y So, (15 + y)/12y = 7/48 60 + 4y = 7y 3y = 60, y = 20 Therefore, 'C' will take 20 days to do the work with 100% efficiency. Work done by all three in one day = 1/20 + 7/48 = (12 + 35)/240 = 47/240 Required number of days = 240/47 days Statement I alone is sufficient to answer the question Statement II: Number of days taken by 'A' to do the work with 100% efficiency = 20 × 4/5= 16 days Let, time taken by 'B' to do the work = x days Then, time taken by 'C' to do the work = (x + 8) days Statement II alone is not sufficient to answer the question.
A solution contains 40% sugar and the rest water. After adding 25 liters of water, we get another solution where the percentage of sugar drops to 20%. T...
The radius of a circle is 14 cm, and the angle subtended by a sector at the center of the circle is 120°. Find the area of the sector.
A man travels 60 km at a speed of 30 km/h and then travels 90 km at a speed of 60 km/h. What is his average speed for the entire journey?
An unknown number is first multiplied by 111 and then 63 is added to it. When the resultant number is divided by 9, the quotient and remainder obtained ...
If sin(3θ) = cos(2θ), find θ.
Jason alone can complete a piece of work in 20 days. In how many days can Jamal alone do the same work, if both of them together can do the same work in...
If the sum of remainders, obtained on dividing 52436 by 22 and 59461 by 73, is divided by 13, then the remainder will be:
Determine the mean of the following observations:
24, 26, 22, 25, 20, 21, 24, 25