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ATQ, Statement I: Let, time taken by 'C' to do the work with 100% efficiency = y days So, time taken by 'C' to do the work with 125% efficiency = 4y/5 days Therefore, time taken by 'A' to do the work = 4y/5 days Work done by 'A' and 'B' in one day = 5/4y + 1/12 = (15 + y)/12y So, (15 + y)/12y = 7/48 60 + 4y = 7y 3y = 60, y = 20 Therefore, 'C' will take 20 days to do the work with 100% efficiency. Work done by all three in one day = 1/20 + 7/48 = (12 + 35)/240 = 47/240 Required number of days = 240/47 days Statement I alone is sufficient to answer the question Statement II: Number of days taken by 'A' to do the work with 100% efficiency = 20 × 4/5= 16 days Let, time taken by 'B' to do the work = x days Then, time taken by 'C' to do the work = (x + 8) days Statement II alone is not sufficient to answer the question.
As per 21st round of Systemic Risk Survey, which of the following risks were assessed as “high”:
In which order did the following Dynasties rule over Delhi?
1. Sayyid Dynasty
2. Lodi Dynasty
3. Tughluq Dynasty
4. Khalji Dynasty
Women 20 Inception meeting under India's G20 Presidency held in which city?
What is the percentage of total Forests cover of the global land area?
Which traditional craft in the Godavari region of Andhra Pradesh received the Geographical Indications (GI) tag?
Deficiency of which of the following vitamins causes excessive bleeding from wounds?
What is the standard size of a singles tennis court?
All fraud cases of value below ₹ 10,000/- involving bank officials, should be referred to the ___ of the bank?