Find the area of a rhombus.
A. Sum of the squares of the diagonals is 256 m².
B. Perimeter of the rhombus is 32 m.
C. Ratio of one diagonal and the side is 3:8
If d₁ and d₂ be the diagonals and a the length of the side of the rhombus then From 1: d₁²+ d₂² = 4a² = 256 a² = 64 a = 8
From 2:
From 3: d₁ : a = 3 : 8
Therefore, by combining C and either A or B, a = 8,d₁ = 3 so we can find d₂ by using, d₁²+ d₂² = 4a² then we can find area of rhombus = 1/2 * d1 * d2 Hence by combining C and either A or B are required to answer as A & B are same.
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