Find the area of a rhombus.
A. Sum of the squares of the diagonals is 256 m².
B. Perimeter of the rhombus is 32 m.
C. Ratio of one diagonal and the side is 3:8
If d₁ and d₂ be the diagonals and a the length of the side of the rhombus then From 1: d₁²+ d₂² = 4a² = 256 a² = 64 a = 8
From 2:
From 3: d₁ : a = 3 : 8
Therefore, by combining C and either A or B, a = 8,d₁ = 3 so we can find d₂ by using, d₁²+ d₂² = 4a² then we can find area of rhombus = 1/2 * d1 * d2 Hence by combining C and either A or B are required to answer as A & B are same.
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * V II. R * V ...
Statement: L = C; E ≥ M ≥ U ≥ C
Conclusion:
I. E > L
II. E = L
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
Statements: A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements: A > C ≥ B = D; E < F = G < H = I ≤ D
Conclusions:
I. B > E
II. D < E
III. E ≥ B
Statements: J $ K, K * T, T @ N, N © R
Conclusions:
I. J $ T II.R * T ...
Statements: O< V ≤ N = P < S, R = Z ≥ Y = X > O
Conclusions:
I. R > N
II. X > P
III. R > O
Statement:X=Y ≥ Z > Q; Y < V ; W < Q
Conclusions:
I. V > W
II. Q > V
Statements: A & D, D # P, P @ Q, Q % R
Conclusions: I. D & R II. Q # A
...
