Question
Suppose Bittu is 50% more efficient than Aman then, what
will be the time taken by Bittu alone to complete 40% of the work. Suppose five friends Ritu, Mohani, Aman, Sam and Kiran are appoints to complete a certain piece of work. Ram and Mohani together can complete a work in 24 days. Mohani and Aman together can complete 50% of the work in 15 days. Aman and Sam together can complete the work in 24 days. Ritu and Kiran together can complete 16.66% of the work in 6 days. Sam and Kiran together can complete the work in 20 days.Solution
ATQ, we can say that Efficiency of, Ram = r, Mohani = m, Aman = a, Sam = s, Kiran = k (r + m) × 24 = (m + a) × 30 = (a + s) × 24 = (r + k) × 36 = (s + e) × 20 = 360 r + m = 15, m + a = 12, a + s = 15, r + k = 10, s + k = 18 (m + a) + (a + d) – (r + m) – (s + k) + (r + k) = 12 + 15 – 15 – 18 + 10 2a = 4 a = 2, m = 10, r = 5, s = 13, k = 5. Hence required time taken by Bittu to complete 40% of work is = (360 × 0.4)/(1.5 × 2) = 144/3 = 48 days
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