Question
If the number of balls faced by Cheteshwar Pujara to
take 1’s is greater than that for 2’s, then he can score a maximum of how many runs? Direction (66 - 70): The table given below shows the scorecard of India during a test match. Some values are missing. Find the answers based on information in table and respective questions.Solution
Runs by 4’s = 4 × 4 = 16 ……………(i)
Number of dot balls = 12
So remaining balls = 41 – (4 + 12) = 25
So, to maximize his score in 25 balls, he can take 13 one’s and 12 two’s. …….…(ii)
So a maximum of 16 + 13 × 1 + 12 × 2 = 53 runs
1240.04 β 360.18 + 449.98 Γ· 15.06 = ?
(√360.99 + 161.14) ÷ 5 × 249.98 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
837.04 Γ 4.02 + 40.04% of 3049.98 β 3667.82 = ? 2 β 60.87
What approximate value should come in the place of question mark in the following questions?
(98.6% of 405.4) β (29.8 Γ 9.7) = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(9/10 of 3999.79) - β2499.83 + (17.81% of 1199.81) = ?
(15.99)2 + 219.98% of 20.01 = ?2 Γ 75.01%
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)