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Start learning 50% faster. Sign in nowIn order to find the minimum score of team, we have to find the minimum runs scored by Pujara. he takes 4 four’s so 4 × 4 = 16 runs So now 41 - 4 = 37 balls left. Now given that he faced 12 white balls, So now balls left = 37 – 12 = 25 balls. Now for minimum runs, he should score more 1’s than 2’s Since at least one 1’s and one 2’s is necessary so minimum runs on 25 balls is 1 × 24 + 2 × 1 So total min runs by Pujara = 4 × 4 + 1 × 24 + 2 × 1 = 42 So minimum score of team = 222 + 80 + 74 + 42 + 26 + 161 = 605
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