Number of chocolates purchased by Sumit from shop A = [(30/100)×200] – 45 = 60 – 45 = 15 Number of chocolates purchased by Sumit from shop B = [(25/100)×200] – 30 = 50 – 30 = 20 Number of chocolates purchased by Sumit from shop D = [(20/100)×200] – 10 = 40 – 10 = 30 Required average = (15 + 20 + 30)/3 = 21.66≈22
20.22% of (74.9 × 6.01) + 69.97 =?
√2023.85 + (24.77% of 1999.73) - (3/8 of 799.91) = ?
(7.992/√?) + √16/? = 14.032/?
(24.98)2 = ?2 + (14.99)2
56237.05 + 10616.99 - 137.25 + 1795.33 = ?
Bijay can complete a task on his own in 40 days, while Ajay can finish the same task in 25 days. If they alternate working on the...
10.992 + (5.01 × 7.98) + ? = 361.03
13.002 × 34.995 + 499.996% of 100.08 + 25.005 % of 3999.997 = ? × 8.908 × 5.909
`11(2/13)` + `5(2/11)` - `3(4/9)` = ?
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?