The number of chocolates distributed in class V is approximately what percentage more/less than the number of chocolates distributed in class III and VI together?
Number of chocolates distributed in class V = (32/100) × 2500 = 800 Number of chocolates distributed in class III and VI together = (25 + 10)% of 2500 = 875 Required difference = [(875 – 800)/875] × 100 = 9% less (approx.)
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