If the shop sold 60% of the total number of pizzas baked by it on the day on which number of regular sized pizzas baked by it is maximum, then find the number of pizzas sold by the shop on the given day.
For Thursday: Total number of Pizzas baked = 160 Sum of the large and medium sized Pizzas baked = 110 So, number of regular sized Pizzas baked = 160 – 110 = 50 Number of regular sized Pizzas baked - Number of large sized cakes baked = 40 Number of large sized Pizzas baked = 50 – 40 = 10 Number of medium sized Pizzas baked = 110 – 10 = 100 Similarly, we can find the required data for the other days too. Maximum number of regular sized pizzas was baked on Friday i.e. 70. Number of pizzas sold by the shop on Friday = (60/100) × 70 = 42
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0