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    Question

    Direction: Five workers – A, B, C, D, and E – are working on a construction project to complete 500 units of work. Each worker works different numbers of hours per day and has varying work efficiencies, which are calculated as the number of units completed per hour. The following table shows the daily working hours and the efficiency (units per hour) for each worker:

    If all five workers start working together, how many

    days will they take to complete the entire 500 units of work?
    A 6.7 days Correct Answer Incorrect Answer
    B 7.2 days Correct Answer Incorrect Answer
    C 5.7 days Correct Answer Incorrect Answer
    D 8.5 days Correct Answer Incorrect Answer
    E 8.7 days Correct Answer Incorrect Answer

    Solution

    Total work done by A in 1 day = 8 × 2 = 16 units. Total work done by B in 1 day = 6 × 3 = 18 units. Total work done by C in 1 day = 5 × 4 = 20 units. Total work done by D in 1 day = 7 × 2.5 = 17.5 units. Total work done by E in 1 day = 9 × 1.8 = 16.2 units. Total units per day by all workers = 16 + 18 + 20 + 17.5 + 16.2 = 87.7 units/day. Days required = 500 ÷ 87.7 ≈ 5.7 days.

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