Question
A reduction of 10% in the price of sugar enables a man
to buy 10 kg more for RS 300. Find the reduced price per kg of sugar.Solution
Due to x% increase/decrease in the price, the person purchased 'y' kg less/more in Rs. 'a' So, we can say that x% of a is the price of y kg  Price of y kg = x% of a Price of 1 kg = (x% of a)/y  Reduced price of per kg sugar = (10% of 300)/10 = (10 x 300)/10 = 3 Rs.
If a = radic;( 3/2) , then radic; (1+a) + radic; (1-a) = ?
...If (6000) 5 = 7.776Â
(64/25)? × (125/512) ? - 1  = 5/8
(0.36) -1.5 = ?
What should come in place of the question mark (?) in the following questions?
417/414Â Â = Â Â ?
If √60 = 7.7 find the value of
(0.09)Â -1.5Â = ?
If 100.9Â = 12 and ( 0.1)x = 120, then what is the value of x.
(0.04) -2.5 = ?
If (5000) 5 = 3.125Â