Question
Find the greatest number 23a68b, which is divisible by 3
but NOT divisible by 9.Solution
For option 1, the sum of the digits = 2 + 3 + 8 + 6 + 8 + 9 = 36 (Divisible by 3 and 9) For option 2, the sum of the digits = 2 + 3 + 9 + 6 + 8 + 5 = 33 (Divisible by 3 but not divisible by 9) For option 3, the sum of the digits = 2 + 3 + 9 + 6 + 8 + 8 = 36 (Divisible by 3 and 9) For option 4, the sum of the digits = 2 + 3 + 7 + 6 + 8 + 7 = 33 (Divisible by 3 but not divisible by 9) So, 239685 and 237687 are divisible by 3 but not divisible by 9 The greatest number among them = 239685 ∴ The greatest number is 239685 which is divisible by 3 but NOT divisible by 9
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 2x2 + 5x + 2 = 0
II. 4y2 = 1
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
Equation 1: x² - 200x + 9600 = 0
Equation 2: y² - 190y + 9025 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 50x + 600 = 0
Equation 2: y² - 51y + 630 = 0
Relevant for Exams:
