18 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 158. Find the square of the sum
Let the three numbers be (a-x), (a), (a+ x) ATQ- a-x +a+ a+ x = 18 3a = 18 a =6 So, numbers 6-x,6,6+x ATQ- (6-x) ² +36 +(6+x) ² = 158 36+x²-12x+36+36+x²+12x = 155 2x² = 158-108 =50 x² = 25 x= 5 So, find the series - 1,6,.11 square of the sum = 324
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