For a number to be divisible by 9, the sum of its digits must also be divisible by 9. Given the number 6428A83, let's find the sum of the known digits and then determine the value of A that makes the entire sum divisible by 9. The sum of the known digits is: 6+4+2+8+8+3= 31 Let the sum of the digits including A be S. Then: S = 31 + A For the number to be divisible by 9, S must also be divisible by 9. So, we need to find the smallest A such that 31 + A is divisible by 9. ATO- The value of A that makes 6428A83 divisible by 9 is 5.
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