A six-digit number 23p7q6 is divisible by 24. Then the greatest possible value for (p + q) is:
23p7q6 will be divisible by 24 = 8 × 3 As we know the divisibility rule of 8 and 3 so, take the maximum value of p and q from 1 to 9. p = 8 and q = 7 the value of p+ q = 7+8 = 15
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