A six-digit number 23p7q6 is divisible by 24. Then the
greatest possible value for (p + q) is:
A18Correct AnswerIncorrect Answer
B20Correct AnswerIncorrect Answer
C15Correct AnswerIncorrect Answer
D24Correct AnswerIncorrect Answer
Solution
23p7q6 will be divisible by 24 = 8 × 3 As we know the divisibility rule of 8 and 3 so, take the maximum value of p and q from 1 to 9. p = 8 and q = 7 the value of p+ q = 7+8 = 15