A six-digit number 27p5q8 is divisible by 36. What is the greatest possible value for (p×q)?
27p5q8 the number must be divisible by both 4 and 9, as 36 is the product of these two numbers. As we know the divisibility rule of 4 and 9 so, take the maximum value of p and q from 1 to 9. p=6 q=8 the greatest possible value of p×q =6×8 =48.
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