If the 9-digit number 5y97405x2, is divisible by 72, find the value of (x – 2y) for the greatest value of x.
For the number 5y97405x2 to be divisible by 72: Divisibility by 8: Last three digits (5x2) must be divisible by 8. For x = 4, (542) is divisible by 8. Divisibility by 9: Sum of digits (36 + y) must be divisible by 9. For (y = 0), (36) is divisible by 9. Thus, with (x = 4) and (y = 0), (x - 2y = 4 - 2(0) = 4.
(150% of 950) ÷ ? = 25
1.55 + 2.05 + 1.5 × 11 – 20% of 10.5 = ?
119 ÷ [22 - {90 ÷ (23 - 105 ÷ (7 × 3))}] = ?
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
54 - 78 + 1518 + 1653 – 1252 = ?
1549.8 ÷ 8.2 + 65.6 × 55 = (? × 4) + (42 × 30.5)
3? x 23 ÷ √ 256 = 40.5
(64/25)? × (125/512)?-1 = 5/8
`(256/6561)(1/4) = ?`
Find the value of x.
√441 ÷ 21+ √400 = 1 × x
