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      Question

      If P = 7 + 4√3 and PQ = 1, then what is the value of

      1/P2Β + 1/Q2?
      A 196 Correct Answer Incorrect Answer
      B 194 Correct Answer Incorrect Answer
      C 206 Correct Answer Incorrect Answer
      D 182 Correct Answer Incorrect Answer

      Solution

      P = 7 + 4√3 PQ=1 Q=1/(7 + 4√3) Rationalizing the denominator i.e multiplying both numerator and denominator with 7 βˆ’ 4√3 Q = 7 βˆ’ 4√3 1 / P2 + 1 / Q2 = P2 + Q2 / P2Q2 = (P+Q)2 βˆ’2PQ / P2Q2 P +Q = 7 + 4√3 + 7 βˆ’ 4√3 P+Q = 14 PQ = 1 Therefore = (196-2)/1 =194

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