If 3x + 5y + 7z = 49 and 9x + 8y + 21z = 126, then what is the value of y?
3x + 5y + 7z = 49 multiplying with 3 on both sides 9x + 15y + 21z = 147 9x + 8y + 21z = 126 Subtracting we get 7y=21 y=3
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