Question
If the nine-digit number 43x1145y2 is divisible by 88,
then the value of (3x — 2y), for the smallest value of y, is:Solution
43x1145y2 5y2 must be divisible by 8 ∴ y = 1 ∴ 512 is divisible by 8 and for divisibility by 11 of 43x114512 (4+x+1+5+2) – (1+4+1+3) should be multiple of 11 ∴ x = 8 Now 3x-2y = 3×8-2×1 = 24-2 = 22
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