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If a + b2 + c2 = 16, x2 + y2 + z2 = 25 and ax + by + cz = 20, then the value of (a+b+c)/(x+y+z)
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- If a + b2 + c2 = 16, x2 + y2 + z2 = 25 and ax + by + cz = 20, then the value of (a+b+c)/(x+y+z)
- is equal to:
- The value of x which satisfies the equation (x+a2+2c2) / (b+c) + (x+b2 +2a2) / (c+a) + (x+c+2b2) / (a+b) = 0 is
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