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For this Question put a = 2, b = 1, c = 1 As we Know Here is only one equation and four variable a, b, c & x, so we can put a, b, c anything else we put a = 2, b = 1, c = 1 On putting ((x+4+2 ) / 2) + ((x+1+8) / 3) + ((x+1+2) / 3) = 0 ⇒ ((6+x)/2) + ((9+x)/3) + ((3+x)/3) = 0 ⇒ 18+3x +18+2x+6 + 2x = 0 ⇒ 7x + 42 = 0, x = - 6 ⇒ putting in option a = 2, b = 1, c = 1 we get option (2) satisfy So = -(a²+b²+c²) = - (4+1+1) ⇒ - 6
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