Question
If sec θ + tan θ = m(> 1), then the value of sin θ is
(0° < θ < 90°)Solution
sec θ + tan θ = m(> 1) let θ = 45° √2 + 1 = m m2 = 3 + 2√2 m2 − 1 = 3 + 2√2 − 1 2 + 2√2 m2 + 1 = 3 + 2√2 + 1 2 + 2√2 m2 −1 / m2+1 = (2+2√2) / (2+2√2) = 1/ √2 = sinθ
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