Question
10 women and 12 men complete a certain piece of work in
30 days, if each women takes thrice the time taken by a man to finish the work. Quantity I – How many days will 17 men and 33 women can take to finish the same work? Quantity II – How many days will 26 men and 12 women can take to finish the same work? In each of the following questions, read the following questions, read the given statements and compare given two quantities on its basis:Solution
17 m + 33 women = 17 m + 11 m = 28 men (in Quantity I). 26 m + 12 women = 26 m + 4 m = 30 men (in Quantity II). Clearly 30 men will take less days to complete a work than 28 men. ∴ Quantity I > Quantity II.
If a3Â + 3a2Â + 9a = 1, then what is the value of a3Â + (3/a)?
(I) 10x2 - 7x + 1 = 0 (II) 35y2 - 12y + 1 =0
If 0 ≤ θ ≤ 90°, and sec107 θ + cos107 θ = 2, then. (secθ + cosθ) is equal to:
If (a2 − b2)sin θ + 2ab cos θ = a2 + b2, then tan θ =
Solve for x (x > 1):
log₃(x − 1) + log₃(x + 1) = 2
If 3x + 5y + 7z = 49 and 9x + 8y + 21z = 126, then what is the value of y?
Quantity I – 3
Quantity II – 254
If > 0 and < 0
If the nine-digit number 43x1145y2 is divisible by 88, then the value of (3x — 2y), for the smallest value of y, is:
If -5 ≤ x ≤ 3 and -1 ≤ y ≤ 0, then the minimum value of 2y – 3x is:
If (a + b)/c = 6/5 and (b + c)/a = 9/2, then what is the value of (a + c)/b?
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