Numerator of a fraction is 4 less than the denominator. If 6 and 7 are added to numerator and denominator of a fraction respectively, then fraction becomes 3/14 more than the initial fraction. Find the sum of numerator and denominator of the initial fraction.
Let the numerator of a fraction = x Denominator = x+4 As per the question, (x+6)/(x+4+7) - (x/(x+4)) (x+6)/(x+11) = (3/14) + x/(x+4) 3x2 +59x-204=0 X= 3, -68/3 X cant be negative Desired sum = 3+3+4 =10
Statements: F @ R, R $ J, V % J, V # Z
Conclusions: I. F * VÂ Â Â Â Â Â Â II. R * VÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â...
Statement: L = C; E ≥ M ≥ U ≥ C
Conclusion:
I. E > L
II. E = L
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements : P > Q < R = U ≤ V = S ≤ W ≥ X > I
Conclusions :
I. Q ≥ V
II. R ≤ W
Statements: Â A % B & G % B; B # L & J; J @ K # S
Conclusions:
I. L @ K
II. A % K
III. S @ B
...Statements: A > C ≥ B = D; E < F = G < H = I ≤ D
Conclusions:
I. B > E
II. D < E
III. E ≥ B
Statements: J $ K, K * T, T @ N, N © R
Conclusions:
 I. J $ T                  II.R * T               Â...
Statements: O< V ≤ N = P < S, R = Z ≥ Y = X > O
Conclusions:
I. R > N
II. X > P
III. R > O
Statement:X=Y ≥ Z > Q; Y < V ; W < Q
Conclusions:
I. V > W
II. Q > V
Statements: A & D, D # P, P @ Q, Q % R
Conclusions: I. D & R                    II. Q # A
...