Question
PQRS is a cyclic quadrilateral of which PQ is the
diameter. Diagonals PR and QS intersect at A. If SQR = 25°, then angle PAS measuresSolution
∠PSQ = 90° ( angle made from the diameter) So ∆PSQ is a right angled triangle. Similarly, ∠PRQ = 90° Now in ∆ARQ ∠ARQ + ∠AQR + ∠QAR = 180° 90°+ 25° + ∠QAR = 180° ∠QAR = 65° ∠QAR = ∠PAS = 65°
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