ABC is a right angled triangle. ∠ BAC = 90o and ∠ ACB = 60o. What is the ratio of the circum radius of the triangle to the side AB?
In a right angled triangle circum radius is half of the hypotenuse AC/2 =R AC=2R Also Sin 60=AB/AC √3 / 2 = AB/AC √3 / 2 = AB/2R R/AB=1: √3
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