in the given figure, ABCD is a square whose side is 4 cm. P is a point on the side AD. What is the minimum value (in cm) of BP + CP ?
In this case if P is the midpoint then we will have the distance BP+CP as minimum since in every other position it will be more than as the distance increases when we go either way of AD Given CD = 4 cm DP = 2 cm CP = √16 + 4 = √20 = 2√5 BP = 2√5 CP+BP = 4√5
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