Question
src="https://www.ixambee.com/questionimage/Section/1647946648-1.PNG" alt="" />
Solution
AD is bisector of ∠ A it divided the BC in ratio of AB : AC = 10 : 15 = 2 : 3 and by PGT = AC = 5√13 DC = 3√13 Let [C = Q0] Now apply sinθ in ∆Abc and in ∆ EDC we get = [sinθ = 10/5√13 = DE/3√13 DE = 6cm
More Geometry Questions
390.11 ÷ 12.98 × 5.14 – 119.9 = √?
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
[(5/6 of 719.81) + 30% of 499.79] × (√99.89 + 25% of 399.69) = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...139.88% of 119.89 + 1451.89 ÷ 6.01 - √196.01 = ? ÷ 3.01 + 215.98
[(120.96 × 12.09) ÷ ?] ÷ 6 = 19.96% of 55.07
766/51 ÷ 387/42 × 121/13 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.99)2 + 219.98% of 20.01 = ?2 × 75.01%
