New SIDBI Grade A New Batch Starts on Nov 18

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    Question

    ∆ ABC is similar to ∆ DEF. If area of ∆ABC is 9 sq.cm and area of ∆DEF is 16 sq.cm and BC = 2.1 cm. Then the length of EF will be

    A 5.6 cm Correct Answer Incorrect Answer
    B 2.8 cm Correct Answer Incorrect Answer
    C 3.7 cm Correct Answer Incorrect Answer
    D 1.4 cm Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    If triangle are similar then (area of △ ABC) /( area of △ DE F) = BC2 / EF2 9/16 = BC2 / EF2 2.1 / EF = 3/4 EF = 2.8 cm

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