Question
A and B are the centres of two circles with radii 11 cm
and 6 cm respectively. A common tangent touches these circles at P & Q respectively. If AB =13 cm, then the length of PQ isSolution
let us assume R a point on AP which is 6 distance form A because QB = 6 if opposite side Same angle 90° then remaining opposite side will be same means AB = RQ = 13 So in ∆PRQ by Pythagoras theorem PQ will be = √(RQ)2 – (PR)2 = √169 – 25 = √144 = 12 Ans
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