In a triangle ABC, the incenter is at O. Find angle BAC if angle BOC=115°.
When the bisector of ∠B and ∠C intersects At the O. Then – ∠BOC =90 ° + ∠A/2 115° =90 + ∠A/2 ∠A/2=25 ° ∠A =25 °×2 =50° ∠A =50°
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