ATQ, Sum of opposite angles of a cyclic quadrilateral is 180° . So, ∠QSR + ∠QPR = 180° Or, 66° + ∠QSR = 180° Or, ∠QSR = 180° – 66° = 114° Sum of linear pairs of angle is 180° . So, ∠QSR + ∠QST = 180° Or, 114° + ∠QS T = 180° Or, ∠QST = 180° – 114° = 66° ST = QT So, ∠SQT = ∠QST (angles opposite to equal sides are equal) Therefore, ∠SQT = 66°
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