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For chord AB, the perpendicular distance from O to AB divides it into two equal halves of 8 cm each. Using Pythagoras in the triangle formed, the perpendicular distance from O to AB = sqrt(10² - 8² ) = sqrt(100 - 64) = sqrt(36) = 6 cm. The chords AB and CD are equidistant from the center, so chord CD is also divided into two equal halves. Length of chord CD = 2 * sqrt(10² - 6² ) = 2 * sqrt(100 - 36) = 2 * sqrt(64) = 16 cm. Correct answer: b) 16 cm
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