If I is the incentre of ΔABC, then ∠ BIC = 90 0 + ∠ BAC/2 112.50 = 90 0 + ∠ BAC /2 112.50 - 90 0 = ∠ BAC/2 ∠ BAC/2 = 22.50 ∠ BAC = 45 0
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