Question

    If in a ΔABC, D is a point on BC such that BD = 2 cm ,

    BC = 6 cm then what is ratio of area of ΔABD to area of ΔADC ?
    A 4:1 Correct Answer Incorrect Answer
    B 2:4 Correct Answer Incorrect Answer
    C 5:9 Correct Answer Incorrect Answer
    D 6:1 Correct Answer Incorrect Answer

    Solution

    CD = BC - BD = 6 - 2 = 4 cm So Area of ΔABD / Area of ΔADC = BD/CD = 2/4

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