If O is circumcentre of acute angled triangle ABC, if ∠OBC = 150 then ∠BAC = ?
∠ OBC =∠ OCB= 150 as radius are equal. ∠ OBC+ ∠ OCB + ∠ BOC =180 0 150 + 150 + ∠ BOC =180 0 So, ∠ BOC = 1500 Now,∠ BOC = 2∠ BAC So,∠ BAC = 1/2 of∠ BOC = 1/2 of 1500 = 750
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